Calculate maximum height, initial velocity, or launch angle for projectile motion using h_max = (v₀² × sin²(θ)) / (2g). Free online physics calculator for kinematics and projectile motion problems.
Calculate maximum height, initial velocity, or launch angle using h_max = (v₀² × sin²(θ)) / (2g)
Maximum Height Formula:
h_max = (v₀² × sin²(θ)) / (2g)
Where: h_max = Maximum Height, v₀ = Initial Velocity, θ = Launch Angle, g = 9.80665 m/s²
Launch angle must be between 0° and 90°
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Maximum height is a key parameter in projectile motion, representing the highest point reached by an object launched into the air. Understanding how to calculate maximum height is essential in physics, engineering, sports science, and ballistics. Our Maximum Height Calculator for Projectile Motion simplifies these calculations, allowing you to determine maximum height, initial velocity, or launch angle using the relationship: h_max = (v₀² × sin²(θ)) / (2g).
Projectile motion describes the path of an object launched into the air under the influence of gravity alone (ignoring air resistance). The maximum height occurs when the vertical component of velocity becomes zero, at which point the object begins descending. Whether you're analyzing sports trajectories, designing projectiles, or studying kinematics, understanding maximum height calculations is fundamental.
Our Maximum Height Calculator offers three calculation modes:
Select your calculation mode, enter the known values with your preferred units, and click Calculate to get instant results with detailed step-by-step solutions. The calculator supports multiple units for velocity (m/s, km/h, mph, ft/s, knots) and height (m, km, cm, ft, in, mi).
The fundamental formula for calculating maximum height in projectile motion is:
Where: h_max = Maximum Height, v₀ = Initial Velocity, θ = Launch Angle, g = Gravitational Acceleration (9.80665 m/s²)
You can rearrange the maximum height formula to solve for any variable:
Maximum height occurs when the vertical component of velocity (v₀ sin(θ)) becomes zero due to gravitational deceleration. At this point, all initial kinetic energy has been converted to potential energy. The formula shows that maximum height depends on the square of initial velocity and the square of the sine of the launch angle, making both factors critical in determining how high a projectile will reach.
Maximum height calculations are essential in numerous applications:
Understanding maximum height requires knowledge of several key concepts:
| Scenario | Initial Velocity | Launch Angle | Maximum Height |
|---|---|---|---|
| Ball thrown straight up | 20 m/s | 90° | 20.39 m |
| Projectile at 45° | 30 m/s | 45° | 22.94 m |
| Shallow launch | 40 m/s | 30° | 20.39 m |
| Steep launch | 25 m/s | 60° | 23.86 m |
*Note: Calculations assume g = 9.80665 m/s² and no air resistance.
Maximum height (h_max) is the highest vertical position reached by a projectile during its flight. It occurs when the vertical component of velocity becomes zero. The maximum height formula is h_max = (v₀² × sin²(θ)) / (2g), where v₀ is initial velocity, θ is launch angle, and g is gravitational acceleration (9.80665 m/s²).
Maximum height is calculated using h_max = (v₀² × sin²(θ)) / (2g). First, determine the initial velocity (v₀) in m/s and launch angle (θ) in degrees. Convert the angle to radians if needed, calculate sin(θ), square it, multiply by v₀², then divide by 2g. For example, with v₀ = 20 m/s and θ = 45°: h_max = (20² × sin²(45°)) / (2 × 9.80665) = (400 × 0.5) / 19.6133 ≈ 10.19 m.
A launch angle of 90° (straight up, vertical) gives the maximum height for a given initial velocity. At 90°, sin(90°) = 1, so the full initial velocity contributes to vertical motion. At any other angle, only the vertical component (v₀ sin(θ)) affects height, which is always less than v₀ for angles less than 90°.
Maximum height increases with the square of initial velocity. Doubling the initial velocity quadruples the maximum height. This is because h_max ∝ v₀² in the formula h_max = (v₀² × sin²(θ)) / (2g). For example, if v₀ = 10 m/s gives h_max = 5 m, then v₀ = 20 m/s gives h_max = 20 m (four times greater).
The time to reach maximum height is t_max = v₀ sin(θ) / g, where v₀ is initial velocity, θ is launch angle, and g is gravitational acceleration. This represents the time until the vertical velocity component becomes zero. For symmetric trajectories (launch and landing at same height), this equals half the total flight time.
No, maximum height depends only on the vertical component of initial velocity (v₀ sin(θ)) and gravity. Horizontal velocity doesn't affect maximum height because motion in horizontal and vertical directions are independent in projectile motion (assuming no air resistance). The horizontal component only affects range, not height.
Maximum height depends on sin²(θ), so it increases as launch angle approaches 90°. At 0° (horizontal), maximum height is zero. At 90° (vertical), maximum height is maximum (v₀² / (2g)). At 45°, maximum height is half the maximum possible height. The relationship is h_max = (v₀² / (2g)) × sin²(θ), showing that sin²(θ) scales the maximum possible height.
Maximum height is a fundamental parameter in projectile motion that helps us understand and predict the behavior of objects launched into the air. Our Maximum Height Calculator for Projectile Motion provides a powerful and accurate tool for determining maximum height, initial velocity, or launch angle using the relationship h_max = (v₀² × sin²(θ)) / (2g).
By simplifying complex kinematics calculations and offering comprehensive unit support with detailed step-by-step solutions, this calculator empowers students, engineers, and physics enthusiasts to analyze projectile motion effectively. For related calculations, explore our Velocity Calculator for velocity calculations or our Acceleration Calculator for acceleration-related physics problems.
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